Forum
Can anyone help me calculate the probability?
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ryonckc wrote
at 12:58 PM, Thursday April 26, 2007 EDT
I lose
7 vs 2 5 vs 2 4 vs 2 2 vs 2 in a single round. What is the probability of that? |
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ryonckc wrote
at 10:02 AM, Friday April 27, 2007 EDT I mean I lose in all the rolls versus 2. Nothing is impossible in this game.
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sarahxxx wrote
at 11:04 AM, Friday April 27, 2007 EDT @fuzz
i stand corrected @tech no need to be patronising u jerk |
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JKD wrote
at 12:22 PM, Friday April 27, 2007 EDT @sarahxxx
no need to be patronising u jerk? ;) |
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failed the Turin wrote
at 12:42 PM, Friday April 27, 2007 EDT I asked vag and he simply said "eleven." Therefore the answer is eleven, and all your Reaganomics are rendered moot. Sorry for any time you may have wasted in your search for the answer.
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fuzzycat wrote
at 12:47 PM, Friday April 27, 2007 EDT ryonckc, you still never mentioned, attacking or defending!
You just have to be more specific if you want precise and correct answers! |
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JKD wrote
at 2:11 PM, Friday April 27, 2007 EDT "in a single round ... I mean I lose in all the rolls versus 2."
That usually means something like he attacked the same land four times. |
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fuzzycat wrote
at 2:40 PM, Friday April 27, 2007 EDT Now next question, did you attack and loose 4 times in a row, are this several attacks, from which you lost 4vs2?
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lick_my_scrotum wrote
at 3:45 PM, Friday April 27, 2007 EDT SORRY ITS TAKEN ME SO LONG TO CORRECT YOU SARAH.
WHEN YOU ARE CALCULATING CONDITIONAL PROBABILITY, YOU MULTIPLY THE < 1 NUMBERS. 7v2 = .00009 5v2 = .00587 4v2 = .03558 2v2 = .44521 WHICH COMES TO 0.000000837% |
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lick_my_scrotum wrote
at 3:47 PM, Friday April 27, 2007 EDT @ FUZZYCAT
WHAT? |
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fuzzycat wrote
at 4:15 PM, Friday April 27, 2007 EDT Do you see this? Press that once! |