approximately 1 in 12 million

well if it's grun's 2 stack, then the probability is like 90% that you will lose them.

everybody knows that.

Are you asking for the probability of it happening to you, or the probability of it happening at all?

Although I refuse to believe you lost a 7v2, unless you were the 2.
7 vs 2 (~0.28%)
5 vs 2 (~0.4%)
4 vs 2 (~5%)
2 vs 2 (50%)

deceptive..

If there are about 30 tables with the game going on, if one game lasts for an about 10 minutes (?)then there are 30*6*24 hours - 4320 games each day.

Lets assume an average game lasts for 15 rounds - and assume that in each round there are 5 players (7 in the beginnig, but fewer at the end)Lets assume in each turn each player makes 2 attacks (once more - an average amount).
4320*15*5*2 = 648000 attacks each day.

So events with probability 1/12.000.000 are bound to happen from time to time.....

tanktunker is wrong with his odds...

7v2 = 0.009%
5v2 = 0.587%
4v2 = 3.558%
2v2 = 44.521%

therefore the chances of it happening in one round is...

0.8368567%

unlucky

hehe

How did you achieve this final number, Sarah?

used me abacus

simple probability equations cleo

http://www.mathgoodies.com/lessons/vol6/independent_events.html

p.s
i used the probability sheet grunvagr gave me

http://img245.imageshack.us/img245/9562/statsbk5.png